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18x^2-6400x+120.800=0
We add all the numbers together, and all the variables
18x^2-6400x+120.8=0
a = 18; b = -6400; c = +120.8;
Δ = b2-4ac
Δ = -64002-4·18·120.8
Δ = 40951302.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6400)-\sqrt{40951302.4}}{2*18}=\frac{6400-\sqrt{40951302.4}}{36} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6400)+\sqrt{40951302.4}}{2*18}=\frac{6400+\sqrt{40951302.4}}{36} $
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